I have an action called List that shows the results of a search. It receives parameters through the querystring because they are optional. My method signature looks like this:
public ActionResult List(List<int> categoryIDs, string school, int? stateID, int? page)
CategoryIDs is a multi-select box and I am doing everything over a GET request. What I need to do is create a link in my view to the next page but retain the same search parameters. I know I can build the link by hand but it is possible to use any of the built-in routing method especially when the categoryIDs have to be formatted like "?categoryID=1&categoryID=2&categoryID=3" to be bound to the list?
Best Answer
I think there's no
ActionLink
overload that helps you do that by default. You need to populate theRouteValueDictionary
instance with the parameters you want to include.For the list of category, try s/t like
categoryIDs=2,3,4,5
etc. since repeating keys are not allowed inRouteValueDictionary
. After that, in the action method will need to parse the string into the integer list.