Linux – How to run crontab job every week on Sunday

crontablinux

I'm trying to figure out how to run a crontab job every week on Sunday. I think the following should work, but I'm not sure if I understand correctly. Is the following correct?

5 8 * * 6

Best Answer

Here is an explanation of the crontab format.

# 1. Entry: Minute when the process will be started [0-60]
# 2. Entry: Hour when the process will be started [0-23]
# 3. Entry: Day of the month when the process will be started [1-28/29/30/31]
# 4. Entry: Month of the year when the process will be started [1-12]
# 5. Entry: Weekday when the process will be started [0-6] [0 is Sunday]
#
# all x min = */x

So according to this your 5 8 * * 0 would run 8:05 every Sunday.

Related Solutions

Linux – How to get a cron job to run every 30 minutes

Do:

0,30 * * * * your_command

Linux – set environment variables that crontab will use

You can define environment variables in the crontab itself when running crontab -e from the command line.

LANG=nb_NO.UTF-8
LC_ALL=nb_NO.UTF-8
# m h  dom mon dow   command

* * * * * sleep 5s && echo "yo"

This feature is only available to certain implementations of cron. Ubuntu and Debian currently use vixie-cron which allows these to be declared in the crontab file (also GNU mcron).

Archlinux and RedHat use cronie which does not allow environment variables to be declared and will throw syntax errors in the cron.log. Workaround can be done per-entry:

# m h  dom mon dow   command
* * * * * export LC_ALL=nb_NO.UTF-8; sleep 5s && echo "yo"

Best Answer

Related Solutions

Linux – How to get a cron job to run every 30 minutes

Linux – set environment variables that crontab will use

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