Linux – Shell command to tar directory excluding certain files/folders

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Is there a simple shell command/script that supports excluding certain files/folders from being archived?

I have a directory that need to be archived with a sub directory that has a number of very large files I do not need to backup.

Not quite solutions:

The tar --exclude=PATTERN command matches the given pattern and excludes those files, but I need specific files & folders to be ignored (full file path), otherwise valid files might be excluded.

I could also use the find command to create a list of files and exclude the ones I don't want to archive and pass the list to tar, but that only works with for a small amount of files. I have tens of thousands.

I'm beginning to think the only solution is to create a file with a list of files/folders to be excluded, then use rsync with --exclude-from=file to copy all the files to a tmp directory, and then use tar to archive that directory.

Can anybody think of a better/more efficient solution?

EDIT: Charles Ma's solution works well. The big gotcha is that the --exclude='./folder' MUST be at the beginning of the tar command. Full command (cd first, so backup is relative to that directory):

cd /folder_to_backup
tar --exclude='./folder' --exclude='./upload/folder2' -zcvf /backup/filename.tgz .

Best Answer

You can have multiple exclude options for tar so

$ tar --exclude='./folder' --exclude='./upload/folder2' -zcvf /backup/filename.tgz .

etc will work. Make sure to put --exclude before the source and destination items.

Related Solutions

Bash – How to check if a directory exists in a Bash shell script

To check if a directory exists in a shell script, you can use the following:

if [ -d "$DIRECTORY" ]; then
  # Control will enter here if $DIRECTORY exists.
fi

Or to check if a directory doesn't exist:

if [ ! -d "$DIRECTORY" ]; then
  # Control will enter here if $DIRECTORY doesn't exist.
fi

However, as Jon Ericson points out, subsequent commands may not work as intended if you do not take into account that a symbolic link to a directory will also pass this check. E.g. running this:

ln -s "$ACTUAL_DIR" "$SYMLINK"
if [ -d "$SYMLINK" ]; then 
  rmdir "$SYMLINK" 
fi

Will produce the error message:

rmdir: failed to remove `symlink': Not a directory

So symbolic links may have to be treated differently, if subsequent commands expect directories:

if [ -d "$LINK_OR_DIR" ]; then 
  if [ -L "$LINK_OR_DIR" ]; then
    # It is a symlink!
    # Symbolic link specific commands go here.
    rm "$LINK_OR_DIR"
  else
    # It's a directory!
    # Directory command goes here.
    rmdir "$LINK_OR_DIR"
  fi
fi

Take particular note of the double-quotes used to wrap the variables. The reason for this is explained by 8jean in another answer.

If the variables contain spaces or other unusual characters it will probably cause the script to fail.

Shell command to sum integers, one per line

Bit of awk should do it?

awk '{s+=$1} END {print s}' mydatafile

Note: some versions of awk have some odd behaviours if you are going to be adding anything exceeding 2^31 (2147483647). See comments for more background. One suggestion is to use printf rather than print:

awk '{s+=$1} END {printf "%.0f", s}' mydatafile

Best Answer

Related Solutions

Bash – How to check if a directory exists in a Bash shell script

Shell command to sum integers, one per line

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