R – strongly typed class in the ViewUserControl not working

asp.net-mvcrenderpartial

I am getting an error in my viewuser control:

Could not load type 'System.Web.Mvc.ViewUserControl'

My viewpage passes the MyViewUserControllerUserList class in the RenderPartial call.

So I am doing:

action creates its strongly typed view data, which has a property which is a strongly typed class that my userlist.ascx expects.

userlist.ascx:

Inherits="System.Web.Mvc.ViewUserControl<MyViewUserControllerUserList>"

Am I doing this correctly?

Update

Just to make sure, my code for my strongly typed partial user control is:

 public class MyViewUserControllerUserList: ViewUserControl 
{

}

Best Answer

The syntax you have looks correct, however you need to make sure the namespace is incuded as well.

Inherits="System.Web.Mvc.ViewUserControl<My.Class.Namespace.ModelClass>"

Then you would pass it in like this

<% Html.RenderPartial("PartialName", InstanceOfModelClass); %>

Then access it inside the partial using the Model property.

Related Solutions

Asp – PartialView is not rendering

Your assumption is incorrect. If you are passing a type of "Personas" to your partial view as it's model, then it needs to inherit System.Web.Mvc.ViewUserControl<Personas>, not the same type as the parent View. The partial view cannot just "know" that your parent view Model type has a property of type Personas and somehow map the object you pass into it to that property.

Also, since you have no literal text being rendered between your server tags, you can shorten your tags to simply:

<% 
   foreach (Personas p in Model.Personas) {
       if (p.DisType == DisType.TextArea) {

         Html.RenderPartial("~/Views/Shared/Controls/Custom/xxx/Textbox", p); 

       }
   }
 %>

Asp.net-mvc – ASP.NET MVC, strongly typed views, partial view parameters glitch

As @Dennis points out, if the model value is null, it will use the existing model from the view. The reason for this is to support the ability to call a partial view using a signature that contains only the partial view name and have it reuse the existing model. Internally, all of the RenderPartial helpers defer to a single RenderPartialInternal method. The way you get that method to reuse the existing model is to pass in a null value for the model (which the signature that takes only a view name does). When you pass a null value to the signature containing both a view name and a model object, you are essentially replicating the behavior of the method that takes only the view name.

This should fix your issue:

<% Html.RenderPartial( "_Bar", Model.Bar ?? string.Empty ) %>

Best Answer

Related Solutions

Asp – PartialView is not rendering

Asp.net-mvc – ASP.NET MVC, strongly typed views, partial view parameters glitch

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