Read all text from a file
Java 11 added the readString() method to read small files as a String
, preserving line terminators:
String content = Files.readString(path, StandardCharsets.US_ASCII);
For versions between Java 7 and 11, here's a compact, robust idiom, wrapped up in a utility method:
static String readFile(String path, Charset encoding)
throws IOException
{
byte[] encoded = Files.readAllBytes(Paths.get(path));
return new String(encoded, encoding);
}
Read lines of text from a file
Java 7 added a convenience method to read a file as lines of text, represented as a List<String>
. This approach is "lossy" because the line separators are stripped from the end of each line.
List<String> lines = Files.readAllLines(Paths.get(path), encoding);
Java 8 added the Files.lines()
method to produce a Stream<String>
. Again, this method is lossy because line separators are stripped. If an IOException
is encountered while reading the file, it is wrapped in an UncheckedIOException
, since Stream
doesn't accept lambdas that throw checked exceptions.
try (Stream<String> lines = Files.lines(path, encoding)) {
lines.forEach(System.out::println);
}
This Stream
does need a close()
call; this is poorly documented on the API, and I suspect many people don't even notice Stream
has a close()
method. Be sure to use an ARM-block as shown.
If you are working with a source other than a file, you can use the lines()
method in BufferedReader
instead.
Memory utilization
The first method, that preserves line breaks, can temporarily require memory several times the size of the file, because for a short time the raw file contents (a byte array), and the decoded characters (each of which is 16 bits even if encoded as 8 bits in the file) reside in memory at once. It is safest to apply to files that you know to be small relative to the available memory.
The second method, reading lines, is usually more memory efficient, because the input byte buffer for decoding doesn't need to contain the entire file. However, it's still not suitable for files that are very large relative to available memory.
For reading large files, you need a different design for your program, one that reads a chunk of text from a stream, processes it, and then moves on to the next, reusing the same fixed-sized memory block. Here, "large" depends on the computer specs. Nowadays, this threshold might be many gigabytes of RAM. The third method, using a Stream<String>
is one way to do this, if your input "records" happen to be individual lines. (Using the readLine()
method of BufferedReader
is the procedural equivalent to this approach.)
Character encoding
One thing that is missing from the sample in the original post is the character encoding. There are some special cases where the platform default is what you want, but they are rare, and you should be able justify your choice.
The StandardCharsets
class defines some constants for the encodings required of all Java runtimes:
String content = readFile("test.txt", StandardCharsets.UTF_8);
The platform default is available from the Charset
class itself:
String content = readFile("test.txt", Charset.defaultCharset());
Note: This answer largely replaces my Java 6 version. The utility of Java 7 safely simplifies the code, and the old answer, which used a mapped byte buffer, prevented the file that was read from being deleted until the mapped buffer was garbage collected. You can view the old version via the "edited" link on this answer.
Try:
git config core.fileMode false
From git-config(1):
core.fileMode
Tells Git if the executable bit of files in the working tree
is to be honored.
Some filesystems lose the executable bit when a file that is
marked as executable is checked out, or checks out a
non-executable file with executable bit on. git-clone(1)
or git-init(1) probe the filesystem to see if it handles the
executable bit correctly and this variable is automatically
set as necessary.
A repository, however, may be on a filesystem that handles
the filemode correctly, and this variable is set to true when
created, but later may be made accessible from another
environment that loses the filemode (e.g. exporting ext4
via CIFS mount, visiting a Cygwin created repository with Git
for Windows or Eclipse). In such a case it may be necessary
to set this variable to false. See git-update-index(1).
The default is true (when core.filemode is not specified
in the config file).
The -c
flag can be used to set this option for one-off commands:
git -c core.fileMode=false diff
And the --global
flag will make it be the default behavior for the logged in user.
git config --global core.fileMode false
Changes of the global setting won't be applied to existing repositories.
Additionally, git clone
and git init
explicitly set core.fileMode
to true
in the repo config as discussed in Git global core.fileMode false overridden locally on clone
Warning
core.fileMode
is not the best practice and should be used carefully. This setting only covers the executable bit of mode and never the read/write bits. In many cases you think you need this setting because you did something like chmod -R 777
, making all your files executable. But in most projects most files don't need and should not be executable for security reasons.
The proper way to solve this kind of situation is to handle folder and file permission separately, with something like:
find . -type d -exec chmod a+rwx {} \; # Make folders traversable and read/write
find . -type f -exec chmod a+rw {} \; # Make files read/write
If you do that, you'll never need to use core.fileMode
, except in very rare environment.
Best Answer
Here's a summary that I have gathered
Explanations:
ls -l
) and everyone else (the public) are able to read the file, but not execute or write to it (permission number 4).There's also an interactive online calculator you can use to figure out what permissions to use: https://chmod-calculator.com/