Swift – the Swift equivalent of isEqualToString in Objective-C

stringswift

I am trying to run the code below:

import UIKit

class LoginViewController: UIViewController {

@IBOutlet var username : UITextField = UITextField()
@IBOutlet var password : UITextField = UITextField()

@IBAction func loginButton(sender : AnyObject) {

    if username .isEqual("") || password.isEqual(""))
    {
        println("Sign in failed. Empty character")
    }
}

My previous code was in Objective-C, which was working fine:

 if([[self.username text] isEqualToString: @""] ||
    [[self.password text] isEqualToString: @""] ) {

I assume I cannot use isEqualToString in Swift. Any help would be appreciated.

Best Answer

With Swift you don't need anymore to check the equality with isEqualToString

You can now use ==

Example:

let x = "hello"
let y = "hello"
let isEqual = (x == y)

now isEqual is true.

Related Solutions

C# – the difference between String and string in C#

string is an alias in C# for System.String.
So technically, there is no difference. It's like int vs. System.Int32.

As far as guidelines, it's generally recommended to use string any time you're referring to an object.

e.g.

string place = "world";

Likewise, I think it's generally recommended to use String if you need to refer specifically to the class.

e.g.

string greet = String.Format("Hello {0}!", place);

This is the style that Microsoft tends to use in their examples.

It appears that the guidance in this area may have changed, as StyleCop now enforces the use of the C# specific aliases.

C++ – How to iterate over the words of a string

I use this to split string by a delimiter. The first puts the results in a pre-constructed vector, the second returns a new vector.

#include <string>
#include <sstream>
#include <vector>
#include <iterator>

template <typename Out>
void split(const std::string &s, char delim, Out result) {
    std::istringstream iss(s);
    std::string item;
    while (std::getline(iss, item, delim)) {
        *result++ = item;
    }
}

std::vector<std::string> split(const std::string &s, char delim) {
    std::vector<std::string> elems;
    split(s, delim, std::back_inserter(elems));
    return elems;
}

Note that this solution does not skip empty tokens, so the following will find 4 items, one of which is empty:

std::vector<std::string> x = split("one:two::three", ':');

Best Answer

Related Solutions

C# – the difference between String and string in C#

This is the style that Microsoft tends to use in their examples.

C++ – How to iterate over the words of a string

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