I would like to establish an IPC connection between several processes on Linux. I have never used UNIX sockets before, and thus I don't know if this is the correct approach to this problem.
One process receives data (unformated, binary) and shall distribute this data via a local AF_UNIX socket using the datagram protocol (i.e. similar to UDP with AF_INET). The data sent from this process to a local Unix socket shall be received by multiple clients listening on the same socket. The number of receivers may vary.
To achieve this the following code is used to create a socket and send data to it (the server process):
struct sockaddr_un ipcFile;
memset(&ipcFile, 0, sizeof(ipcFile));
ipcFile.sun_family = AF_UNIX;
strcpy(ipcFile.sun_path, filename.c_str());
int socket = socket(AF_UNIX, SOCK_DGRAM, 0);
bind(socket, (struct sockaddr *) &ipcFile, sizeof(ipcFile));
...
// buf contains the data, buflen contains the number of bytes
int bytes = write(socket, buf, buflen);
...
close(socket);
unlink(ipcFile.sun_path);
This write returns -1 with errno reporting ENOTCONN ("Transport endpoint is not connected"). I guess this is because no receiving process is currently listening to this local socket, correct?
Then, I tried to create a client who connects to this socket.
struct sockaddr_un ipcFile;
memset(&ipcFile, 0, sizeof(ipcFile));
ipcFile.sun_family = AF_UNIX;
strcpy(ipcFile.sun_path, filename.c_str());
int socket = socket(AF_UNIX, SOCK_DGRAM, 0);
bind(socket, (struct sockaddr *) &ipcFile, sizeof(ipcFile));
...
char buf[1024];
int bytes = read(socket, buf, sizeof(buf));
...
close(socket);
Here, the bind fails ("Address already in use"). So, do I need to set some socket options, or is this generally the wrong approach?
Thanks in advance for any comments / solutions!
Best Answer
There's a trick to using Unix Domain Socket with datagram configuration. Unlike stream sockets (tcp or unix domain socket), datagram sockets need endpoints defined for both the server AND the client. When one establishes a connection in stream sockets, an endpoint for the client is implicitly created by the operating system. Whether this corresponds to an ephemeral TCP/UDP port, or a temporary inode for the unix domain, the endpoint for the client is created for you. Thats why you don't normally need to issue a call to bind() for stream sockets in the client.
The reason you're seeing "Address already in use" is because you're telling the client to bind to the same address as the server.
bind()
is about asserting external identity. Two sockets can't normally have the same name.With datagram sockets, specifically unix domain datagram sockets, the client has to
bind()
to its own endpoint, thenconnect()
to the server's endpoint. Here is your client code, slightly modified, with some other goodies thrown in:At this point your socket should be fully setup. I think theoretically you can use
read()
/write()
, but usually I'd usesend()
/recv()
for datagram sockets.Normally you'll want to check error after each of these calls and issue a
perror()
afterwards. It will greatly aid you when things go wrong. In general, use a pattern like this:This goes for pretty much any C system calls.
The best reference for this is Steven's "Unix Network Programming". In the 3rd edition, section 15.4, pages 415-419 show some examples and lists many of the caveats.
By the way, in reference to
I think you're right about the ENOTCONN error from
write()
in the server. A UDP socket would normally not complain because it has no facility to know if the client process is listening. However, unix domain datagram sockets are different. In fact, thewrite()
will actually block if the client's receive buffer is full rather than drop the packet. This makes unix domain datagram sockets much superior to UDP for IPC because UDP will most certainly drop packets when under load, even on localhost. On the other hand, it means you have to be careful with fast writers and slow readers.