Ruby – Convert string numbers( in word format) to integer ruby

ruby

If you have a string ten, is it possible to convert it to an integer 10 in Ruby? (maybe in rails?)

I value the developers at tryruby.org, and in their tutorial here, it specifically says "to_i converts things to integers (numbers.)" I am wondering why they didn't say "to_i converts STRINGS to integers (numbers.)"

What variable types can be converted from their type to an integer?

Best Answer

Check out this gem for handling word to number conversions.

From the readme:

require 'numbers_in_words'
require 'numbers_in_words/duck_punch'

112.in_words
#=> one hundred and twelve
"Seventy million, five-hundred and fifty six thousand point eight nine three".in_numbers
#=> 70556000.893

Related Solutions

Ruby-on-rails – How to “pretty” format JSON output in Ruby on Rails

Use the pretty_generate() function, built into later versions of JSON. For example:

require 'json'
my_object = { :array => [1, 2, 3, { :sample => "hash"} ], :foo => "bar" }
puts JSON.pretty_generate(my_object)

Which gets you:

{
  "array": [
    1,
    2,
    3,
    {
      "sample": "hash"
    }
  ],
  "foo": "bar"
}

Ruby – How to generate a random string in Ruby

(0...8).map { (65 + rand(26)).chr }.join

I spend too much time golfing.

(0...50).map { ('a'..'z').to_a[rand(26)] }.join

And a last one that's even more confusing, but more flexible and wastes fewer cycles:

o = [('a'..'z'), ('A'..'Z')].map(&:to_a).flatten
string = (0...50).map { o[rand(o.length)] }.join

If you want to generate some random text then use the following:

50.times.map { (0...(rand(10))).map { ('a'..'z').to_a[rand(26)] }.join }.join(" ")

this code generates 50 random word string with words length less than 10 characters and then join with space

Best Answer

Related Solutions

Ruby-on-rails – How to “pretty” format JSON output in Ruby on Rails

Ruby – How to generate a random string in Ruby

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