Scala – Escape a dollar sign in string interpolation

scalastring-interpolation

How do I escape a dollar sign in string interpolation?

def getCompanion(name: String) = Class.forName(s"my.package.$name\$")

// --> "error: unclosed string literal"

Best Answer

Just double it

scala> val name = "foo"
name: String = foo

scala> s"my.package.$name$$"
res0: String = my.package.foo$

Related Solutions

Javascript – How to do string interpolation in JavaScript

Since ES6, you can use template literals:

const age = 3
console.log(`I'm ${age} years old!`)

P.S. Note the use of backticks: ``.

Python – Python equivalent to Ruby’s string interpolation

Python 3.6 will add literal string interpolation similar to Ruby's string interpolation. Starting with that version of Python (which is scheduled to be released by the end of 2016), you will be able to include expressions in "f-strings", e.g.

name = "Spongebob Squarepants"
print(f"Who lives in a Pineapple under the sea? {name}.")

Prior to 3.6, the closest you can get to this is

name = "Spongebob Squarepants"
print("Who lives in a Pineapple under the sea? %(name)s." % locals())

The % operator can be used for string interpolation in Python. The first operand is the string to be interpolated, the second can have different types including a "mapping", mapping field names to the values to be interpolated. Here I used the dictionary of local variables locals() to map the field name name to its value as a local variable.

The same code using the .format() method of recent Python versions would look like this:

name = "Spongebob Squarepants"
print("Who lives in a Pineapple under the sea? {name!s}.".format(**locals()))

There is also the string.Template class:

tmpl = string.Template("Who lives in a Pineapple under the sea? $name.")
print(tmpl.substitute(name="Spongebob Squarepants"))

Best Answer

Related Solutions

Javascript – How to do string interpolation in JavaScript

Python – Python equivalent to Ruby’s string interpolation

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