I am trying get a day name like friday, saturday, sunday, monday etc from a given date. I know there is a built in function which returns the day name for example:
SELECT DATENAME(dw,'09/23/2013') as theDayName
this SQL query returns:
'Monday'
This is all OK. But I would like to pass Month, Day and Year
individually.
I am using the builtin DATEPART function to retrieve month, day and year from a date so I can pass it to the DATENAME function:
SELECT DATEPART(m, GETDATE()) as theMonth -- returns 11
SELECT DATEPART(d, GETDATE()) as theDay -- returns 20
SELECT DATEPART(yy, GETDATE()) as theYear -- returns 2013
Now that I have Month, Day, Year values individually, I pass it to my DATENAME
to get the Weekname
of the date I want:
--my SQL query to return dayName
SELECT (DATENAME(dw, DATEPART(m, GETDATE())/DATEPART(d, myDateCol1)/ DATEPART(yy, getdate()))) as myNameOfDay, FirstName, LastName FROM myTable
This returns an incorrect Day Name. I tried replace / with – so that in the DATENAME function my SQL query becomes:
SELECT DATENAME(dw,'09/23/2013')
--becomes
SELECT DATENAME(dw,'09-23-2013')
but it still returns incorrect dayName from my SQL query. Am I missing something here.
Please advise.
Best Answer
Tested and works on SQL 2005 and 2008. Not sure if this works in 2012 and later.
The solution uses DATENAME instead of DATEPART
This is work in sql 2014 also.