Sql – Select most recent record based on date

sqlsql server

I'm trying to create a select query that returns the most recent record from the table based on date. Basically whichever row's [Date] field is closest to the current date.

Sample Data:

    ID       Content         Date
--------------------------------------------
1   1050    Test Values    2013-11-27 10:46:24.900
2   1051    Test Test      2013-11-27 10:47:43.150
3   1057    Test Testx2    2013-11-27 10:48:22.820

I would like to only return these values

    ID       Content         Date
--------------------------------------------
1   1057    Test Testx2    2013-11-27 10:48:22.820

Thanks!

Best Answer

You could try the following query:

SELECT TOP 1 *
FROM Table
ORDER BY [Date] DESC

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Sql – Insert into … values ( SELECT … FROM … )

Try:

INSERT INTO table1 ( column1 )
SELECT  col1
FROM    table2

This is standard ANSI SQL and should work on any DBMS

It definitely works for:

Oracle
MS SQL Server
MySQL
Postgres
SQLite v3
Teradata
DB2
Sybase
Vertica
HSQLDB
H2
AWS RedShift
SAP HANA
Google Spanner

Sql – How to perform an IF…THEN in an SQL SELECT

The CASE statement is the closest to IF in SQL and is supported on all versions of SQL Server.

SELECT CAST(
             CASE
                  WHEN Obsolete = 'N' or InStock = 'Y'
                     THEN 1
                  ELSE 0
             END AS bit) as Saleable, *
FROM Product

You only need to use the CAST operator if you want the result as a Boolean value. If you are happy with an int, this works:

SELECT CASE
            WHEN Obsolete = 'N' or InStock = 'Y'
               THEN 1
               ELSE 0
       END as Saleable, *
FROM Product

CASE statements can be embedded in other CASE statements and even included in aggregates.

SQL Server Denali (SQL Server 2012) adds the IIF statement which is also available in access (pointed out by Martin Smith):

SELECT IIF(Obsolete = 'N' or InStock = 'Y', 1, 0) as Saleable, * FROM Product

Best Answer

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