Why does Lua have no “continue” statement

break will exit the loop completely, continue will just skip the current iteration.

For example:

for (int i = 0; i < 10; i++) {
    if (i == 0) {
        break;
    }

    DoSomeThingWith(i);
}

The break will cause the loop to exit on the first iteration - DoSomeThingWith will never be executed. This here:

for (int i = 0; i < 10; i++) {
    if(i == 0) {
        continue;
    }

    DoSomeThingWith(i);
}

Will not execute DoSomeThingWith for i = 0, but the loop will continue and DoSomeThingWith will be executed for i = 1 to i = 9.

def chunker(seq, size):
    return (seq[pos:pos + size] for pos in range(0, len(seq), size))
# (in python 2 use xrange() instead of range() to avoid allocating a list)

Works with any sequence:

text = "I am a very, very helpful text"

for group in chunker(text, 7):
   print(repr(group),)
# 'I am a ' 'very, v' 'ery hel' 'pful te' 'xt'

print '|'.join(chunker(text, 10))
# I am a ver|y, very he|lpful text

animals = ['cat', 'dog', 'rabbit', 'duck', 'bird', 'cow', 'gnu', 'fish']

for group in chunker(animals, 3):
    print(group)
# ['cat', 'dog', 'rabbit']
# ['duck', 'bird', 'cow']
# ['gnu', 'fish']