Xml – Accessing child nodes of xml by name in Groovy while accessing parent node iteratively

groovysoapuixml

I have an XML like this:

<Envelope>
 <Node>
    <Status>1</Status>
    <Name1>John</Name1>
    <Name2>Smith</Name2>
 </Node>
 <Node>
    <Status>2</Status>
    <Name1>Jane</Name1>
    <Name2>Doe</Name2>
 </Node>
</Envelope>

I want to iterate through each node and if the value of Status is 1, use Name1 and if it is 2, use Name2.

Envelope = holder.getNodeValues("//ns2:NonProvisionedServers")
for(node in Envelope)
if(node.Status == 1)
{
    assert node.Name1 == "SomeFirstName"
}
if(node.Status == 2)
{
    assert node.Name2 == "SomeLastName"
}

I have done minimal Groovy scripting before. I've seen related posts but they only iterate through the child nodes, which I don't want to do since my parent node has a lot of child nodes, and I've a lot of parent nodes to go through. Any help would be appreciated.

Best Answer

You can do it this way:

def inx = '''<Envelope>
            |  <Node>
            |    <Status>1</Status>
            |    <Name1>John</Name1>
            |    <Name2>Smith</Name2>
            |  </Node>
            |  <Node>
            |    <Status>2</Status>
            |    <Name1>Jane</Name1>
            |    <Name2>Doe</Name2>
            |  </Node>
            |</Envelope>'''.stripMargin()

// Parse the XML
def xml = new XmlSlurper().parseText( inx )

// For every <Node> element in the XML
xml.Node.each { node ->

  // Print the child of the node called "Name" + Status
  println node."Name${node.Status}"
}

That prints:

John
Doe

Related Solutions

Xml – Groovy – how to exit each loop

You cannot do it elegantly. You might see some people suggest throwing an Exception, but that's just plain ugly.

Here's some mailing list discussion on using each vs. for, and a couple people say that for is preferred because of each's inability to break from the iteration.

Your best bet is probably to change over to a for loop and iterate:

for(def domain : records.children()) { // this may need some tweaking depending on types
    // do stuff
    if(condition) {
        break;
    }
}

Either that, or like you said, maybe use find or findAll to find the element you're looking for (the following code is paraphrased, I don't have time yet to test it out):

def result = records.children().find { domain -> domain.@domain_name == targetDomain }
result.children().each {
    // print stuff
}

Xml – Representing a graph in XML

Since you have a graph, and not a tree as you first thought, why not use GraphML?

GraphML is a comprehensive and easy-to-use file format for graphs. It consists of a language core to describe the structural properties of a graph and a flexible extension mechanism to add application-specific data.

Unlike many other file formats for graphs, GraphML does not use a custom syntax. Instead, it is based on XML and hence ideally suited as a common denominator for all kinds of services generating, archiving, or processing graphs.

Best Answer

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