Xml – How to dynamically get value attribute value of a row using XSLT

xmlxslt

I have to create one table using XSLT and CSS. The table should look like

                ID    FNAME
                 1    AA
                 2    BB

XML:

<students>
    <studentDetails  id="1" fname="AA"/>
    <studentDetails  id="2" fname="BB"/>
</students>

XSLT so far:
I have traverse upto studentDetails and then

<td >
      <xsl:call-template name="zz">
      <xsl:with-param name="child-name" select="'id'"/>
      </xsl:call-template>
    </td>
     <xsl:template name="zz">
<xsl:param name="child-name"/>

<xsl:value-of select="*[name(@id) = $child-name]"/>//should print 1 and then 2 in next row

Can somebody suggest where i am going wrong?

Best Answer

At first don't pass "'id'" just use "id" At second = pattern * selects node, but you need attr (@*), so you need write:

<xsl:value-of select="@*[name()=$child-name]"/>

Related Solutions

Xml – How to dynamically get value of a row using XSLT

You could use <xsl:for-each>, but I think this is more concise, and extensible to arbitrarily many columns (so long as they're all the same):

<xsl:stylesheet version="1.0" xmlns:xs="...">

  <xsl:template match="students">
    <div>
      <div class="idcol">
        <div class="header">
          <xsl:text>ID</xsl:text>
        </div>
        <xsl:apply-templates>
          <xsl:with-param name="child-name" select="'id'"/>
        </xsl:apply-templates>
      </div>
      <div class="fnamecol">
        <div class="header">
          <xsl:text>FNAME</xsl:text>
        </div>
        <xsl:apply-templates>
          <xsl:with-param name="child-name" select="'fname'"/>
        </xsl:apply-templates>
      </div>
    </div>
  </xsl:template>

  <xsl:template match="studentDetails">
    <xsl:param name="child-name"/>
    <div class="row">
      <xsl:value-of select="*[name() = $child-name]"/>
    </div>
  </xsl:template>

</xsl:stylesheet>

XSLT – Adding Elements dynamically

What would happen if more job roles, other than Dev and QA got added? Would your stylesheet be able to cope? Maybe you can make use of Muenchian Grouping to get all possible roles in the stylesheet, and then generate columns for each possible role dynamically?

<xsl:key name="roles" match="role" use="."/>

<xsl:template match="/projectteam">
 <table border="1">
  <tr>
   <td>Name</td>
   <td>Role</td>
   <xsl:for-each select="member[generate-id(role) = generate-id(key('roles', role)[1])]">
    <td>
     <xsl:value-of select="role"/>
    </td>
   </xsl:for-each>
  </tr>
  <xsl:apply-templates select="member"/>
 </table>
</xsl:template>

<xsl:template match="member">
 <xsl:variable name="currentrole" select="role"/>
 <xsl:variable name="currenthrs" select="hrs"/>
 <tr>
  <td>
   <xsl:value-of select="name"/>
  </td>
  <td>
   <xsl:value-of select="role"/>
  </td>
  <xsl:for-each select="/projectteam/member[generate-id(role) = generate-id(key('roles', role)[1])]">
   <td>
    <xsl:choose>
     <xsl:when test="$currentrole = role">
      <xsl:value-of select="$currenthrs"/>
     </xsl:when>
    </xsl:choose>
   </td>
  </xsl:for-each>
 </tr>
</xsl:template>

I've outputted as HTML, not XSL-FO, but maybe this gives you the general idea.

Best Answer

Related Solutions

Xml – How to dynamically get value of a row using XSLT

XSLT – Adding Elements dynamically

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