Google Sheets – Return Unique Values Based on Part of String

I have a list of values as follows:

Maestro purchase 28.02.2019 18:54 Coop-4853 ZH Bombach Card number: 79090775                
Payment order               
Maestro purchase 27.02.2019 08:29 VBZ FRANKENTAL Card number: 79111775              
Maestro purchase 27.02.2019 17:48 VBZ SIHLQUAI/HB Card number: 79111775             
Maestro purchase 27.02.2019 08:29 VBZ FRANKENTAL Card number: 79111775              
Debit LSV+ VISECA CARD SERVICES SA              
Maestro purchase 27.02.2019 18:36 Coop-4853 ZH Bombach Card number: 79111775                
Maestro purchase 25.02.2019 14:32 VBZ ZURICH VERKEHRSB Card number: 79111776                
Maestro purchase 25.02.2019 16:21 Gemeinde Oberengstri Card number: 79111776                
Maestro purchase 23.02.2019 14:39 VBZ FRANKENTAL Card number: 79111776              
Maestro purchase 23.02.2019 15:27 VBZ MEIERHOFPLATZ Card number: 79111776               
Credit              
Maestro purchase 23.02.2019 15:21 Coop-1906 ZH Höngger Card number: 79111776                
Maestro purchase 22.02.2019 11:12 VBZ FRANKENTAL Card number: 79111776              
Maestro purchase 21.02.2019 07:36 VBZ FRANKENTAL Card number: 79111775  

I'd like to have one function that returns a list of all unique occurrences based on this rule:

IF the string starts with Maestro extract the string in between the first 34 chars and the last 22

[34 chars] "String to be extracted" [22 chars]

IF the string does not start with Maestro, then get the full string.

I was able to extract the strings based on the rule above with this function IFERROR(MID(A2,35,LEN(A2)-56),A2) but somehow I got stuck because I might have to wrap everything in an array formula or something.

If it helps here's a spreadsheet with the data:

https://docs.google.com/spreadsheets/d/1SPsZSVRMVZDDlYV7MovJ__0hkIMlXHTWg4Eq5_20gxw/edit?usp=sharing