I'm trying to create a case list filter in CommCare. Specifically I want to create a filter such that a case property (interviewer_username) is equal to the username of the person who is logged in. I have seen the instructions for how to do this using custom user data and the mobile worker first/last name, but how do you reference the username itself?
CommCare – How to Reference Mobile Worker’s Username in Case List Filter
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Related Solutions
One way to accomplish this is by loading the label text in a hidden variable's Calculate Condition and then reference that variable later.
Create a hidden variable with your label text
Add the label text to the Calculate Condition of a hidden variable question type. For example, my_label_text
Reference that variable in a question's label text box
You can drag and drop that hidden variable, my_label_text, into the label portion of the question:
Save the hidden variable to a case property
You can then add logic to save my_label_text as a case property in the Case Management tab. In your scenario you may also want to add logic to save whether or not the question was answered properly.
This normally requires a Pro Plan to setup for your project. I think your project may have an older version of the Pro Plan and needs to updated to the newest one. Once that's done, Cory's solution will work.
Related Topic
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- How to see what case/report/user data a CommCare user has access to on mobile
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Best Answer
You can access the
usernameof a user in the case list filter with this syntax:More information can be found here: https://confluence.dimagi.com/display/commcarepublic/User+Case. The username isn't stored in Custom User Data, but rather the User Case.