Create a totem-pole structure by using two optocouplers

Use a comparator circuit to convert your "feeble" function generator signal to a decent square wave. This will be suitable for driving the opto's "LED" (via the appropriate value resistor). I'd use a fast-ish op-amp for simplicity like the AD8605 - it has a 10MHz bandwidth and is more than capable of driving an opto (given the slowness of most optos). Don't forget to add a little hysteresis - probably about 1% to prevent multiple glitches as the waveform (and noise) pass the comparator trigger point.

There may be another problem of course - your function generator may have a DC offset pot and this may be set so that the waveform output never gets low enough to turn the opto LED off.

EDIT

The OP has now stated that the Opto is a PC817 and that they wish to work with frequencies upto 30kHz. The Opto specified has a max rise time and fall time of 18 us and this means the opto isn't suitable and is likely to be the cause of the problem: -

Note that it states the cut-off frequency is 80kHz (typically) and at this frequency the output from the Opto is going to be very poor in rise time and fall time (about 4us) but it's worse if you took maximum limits into consideration. If you can live with the asymmetrical mark-space ratios and the delay then consider adding a comparator stage between opto and arduino - if you can't then choose a faster device.

These transistors don't conduct unless Vbe>0.6V for the NPN, Vbe<-0.6V for the PNP. And as the bases and emitters are tied together, it is impossible for both these conditions to be true at the same time. So when one transistor is turned on, the other is turned off.

HOWEVER

if R2 is too low, the transistor being turned on will "saturate". And when saturated, it will take a significant time to turn off after the base current is removed. This question and answers discuss one famous solution to that problem.

However the present value of R2 limits the base current, because the voltage across R2 will be relatively low, so the transistors will not saturate hard and will turn off relatively fast.