Electrical – Building 3-8 decoder with two 2-4 decoders and a few additional gates

decoder

I am trying to build a 3-8 decoder without an enable by using two 2-4 decoders (that also don't have enables), two chips that each contain 4 AND gates, and one chip that contains 4 NOT gates.

I have tried to base my solution on this answer:
Design a 3-to-8 Decoder Using Only Three 2-to-4 Decoders

but I have not been able to figure it out.

Thanks in advance.

Best Answer

Start by creating an enable function.

schematic

simulate this circuit – Schematic created using CircuitLab

Does this give you any ideas? (Hint, you'll only need a single NOR gate to decode the enables.)

Related Topic