Electrical – Duty cycle calculation

dc motorduty cyclehomeworkmotorpwm

I am trying to solve a numerical where the Speed of a DC motor operating at 15V was measured to be 2000 rad/sec. Now a PWM signal is applied to the same motor to get a speed of 400 rad/sec. If the voltage amplitude of the PWM signal is 5V, then what should be the value of duty cycle?

I know the formula of duty cycle is

D=Vout/Vin

D=duty cycle

Vin=15V

Vout=5V

therefore the duty cycle is =5/15

i.e 1/3

therefore duty cycle in percentage is 33.33%

is my calculation right or whether I have to consider the speed of motor at 15V(2000 rad/sec) and at 5V(400 rad/sec)? If yes then how?

this the exact question

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Best Answer

When you go from 15V to 5V, you get \${5 \over 15} = {1 \over 3}\$ of the original speed.

What you actually want \${400 \over 2000} = {1 \over 5}\$ of the original speed, so you will somehow have to reduce the speed further by "PWM-ing your way" from \$1 \over 3\$ to \$1 \over 5\$ of the original speed. So:

\${1 \over 3} \times dutycycle = {1 \over 5} \implies dutycycle = {3 \over 5} = 60\%\$

Going from 15V to 5V has reduced the speed to \${2000 \over 3} \mathrm{\, rad/s}\$, reducing the speed further to 60% of that gives \$60\% \times {2000 \over 3} = 400 \mathrm{\, rad/s}.\$