Electrical – Inductive sensors for traffic lights

inductiveinductorproximity-sensor

I have read that the inductors are imbedded in asphalts in small cities and this is how the traffic light detects if a car is approaching.

I have two question.

1- So if they are embedded would the magnetic field be strong enough to pass the asphalt without attenuation?

2- The cores of the inductors remain the same and what is changing is not the magnetic filed inside, but outside. From the basic physics we know that
the change in inductance depends on the permeability of the core, area of the core and the length of the wire. So nothing in core changes when a car stops on top of an inductor. So the question is how would the voltage changes in this case?

Best Answer

Inductive traffic loops work by embedding one or more series-connected loops of wire in a slot cut in the road surface. (Typically one to three turns are used.) The two ends are connected back to a control box. The loop forms and inductive coil which is used as part of an oscillator circuit in the control box.

Loop inductance is not affected by asphalt or concrete as they typically don't contain any metal. The presence of a vehicle, however, will affect the inductance of the loop and a change in frequency of the oscillator will result. When the frequency change is large enough the controller will switch its output to signal vehicle present.

To answer your specific questions:

1- So if they are embedded would the magnetic field be strong enough to pass the asphalt without attenuation?

The asphalt (or concrete) does not affect the inductance of the loop. I can't find any figures but I suspect its permeability is going to be very much closer to that of air than that of iron, for example.

2- The cores of the inductors remain the same and what is changing is not the magnetic filed inside, but outside. From the basic physics we know that the change in inductance depends on the permeability of the core, area of the core and the length of the wire. So nothing in core changes when a car stops on top of an inductor.

The inductor is, effectively, air-cored. There is no metal involved until a vehicle arrives and it becomes the core. The sensing height will depend on the length of the shortest side of the loop - see below. This makes intuitive sense. Think of an inductor wound on a cardboard tube with a steel rod sliding in and out: It will have to get close to the coil before it starts to make a difference. An interesting though on this is that we could make much more sensitive drive-through loops - much like airport metal detectors - but this has not been considered a good idea for obvious reasons.

So the question is how would the voltage changes in this case?

The voltage might not change but the oscillator frequency will. The frequency of an LC (inductor-capacitor) oscillator is given by

$$f = \frac {1}{2 \pi \sqrt{LC}}$$

so we can see that if L increases with the presence of a vehicle the frequency will drop.


There is an interesting presentation PDF from Eberle Design Inc. which addresses the installation of inductive traffic loops. Extracts below.

a. The typical sensing height is 2/3 of the shortest leg of a loop (in feet). Therefore a 4’ x 8’ loop typically has a detection height of 2.66 feet.

b. The inductance of a conventional four-sided loop can be estimated using the formula: \$L = P \times (T^2 + T) / 4\$ Where L = Loop Inductance in micro Henries, P = Loop Perimeter in feet and T = Number of turns of wires in saw slot.

Therefore a 4’ x 8’ loop with 4 turns would be: \$L = (4 + 8 + 4 + 8) (4^2+ 4) / 4 = 24 (16 + 4) / 4 = 24 \cdot 20 / 4 = 24 \cdot 5 = 120~\mu H\$ Note: Loop feeder cable typically adds 0.22 micro Henries of inductance per foot of cable.

The article also covers series connection of loops and how to install loops on both sides of a sliding gate while avoiding detection of the gate.