Power Engineering – Understanding Instantaneous Power

power-engineering

A sinusoidal voltage source v =10V sin(ωt) is connected across a 1k resistor.

  1. Make a sketch of p(t), the instantaneous power supplied by the source.
  2. Determine the average power supplied by the source.
  3. Now, suppose that a square wave generator is used as the source. If the square wave signal has a peak-to-peak of 20 V and a zero average value, determine the average power supplied by the source.
  4. Next, if the square wave signal has a peak-to-peak of 20 V and a 10 V average value, determine the average power supplied by the source.

This image has the picture of my partial solution:

the image has the picture of my partial solution

Best Answer

Your answer to part 2 is correct (although I didn't check all of the intermediate steps). The plot of instantaneous power is a sine wave that has a minimum of zero and a maximum of \$\frac{{10 V}^2}{1000 \Omega} = 0.1 W\$. The average value of this waveform is half the peak, or 0.05 W.

The same analysis for the square waves is quite straightforward. In either case, there are only two values of instantaneous power that you need to consider.