I have sampled values of voltage (phase to ground) and current (line current). I can calculate instantaneous apparent power using:

$$ P(i) = V_1(i)I_1(i) +V_2(i)I_2(i) +V_3(i)I_3(i), i\in [1,n]$$

Question: Is there a method to calculate instantaneous active (or reactive) power from sampled data instead of apparent power?

## Best Answer

Instantaneous power is simply the instantaneous voltage times instantaneous current. This is true regardless of the power factor, amount of "reactive power", phase angle, or any other way of expressing this same issue.

To determine phase angle (or power factor, "reactive power", etc) takes more than one reading. Average real power is the average of instantaneous power.

real power = ave(volt x amps)

The power factor is the real power divided by the "VA" (volt-amps):

power factor = (real power) / (RMS(volts) * RMS(amps))

From that you can calculate the real and imaginary components of the power, and the phase angle if you know the waveshape.