Electrical – Simplest shift register test circuit – clock

I'm looking for the simplest way to test the operation of a 74HC595 shift register without complex circuitry.

Currently (on a breadboard) I have a 47K SIP resistor in a pull-up fashion connected to pins 9 through 14 to make all inputs a default high. Yes I'm aware pin 9 is meant as n output and I'd be wasting some current if output of that pin is high but that particular output is useless to me anyway.

I then select random Qx output pins to connect directly to LEDs through current limiting resistors.

So I begin my tests and determined that the data line (pin 14) works, and enable (pin 13) also works, and the store clock (pin 12) also works along with the reset (pin 10) works.

But the clock (pin 11) is hard to tell if it is working because I need to pulse it faster than the fastest typist which I can't do. Every time I pulse it (make clock line low then make clock line high about 1/2 second later) after inverting the input data line, it seems all data output changes to the new input value instead of just one data output line.

So then I added a 10uF capacitor between clock (pin 11) which is the capacitor across the "wire" button in an effort to eliminate "bouncing", but that method isn't working.

So is there a simple way to test this clock line so that the IC sees that only one clock pulse occurred rather than hundreds of pulses?

The only answer I can come up with so far is to make an oscillator and connect it's output to the clock but I want to avoid too many extra chips if possible. Heck, if I can rewire my capacitor or resistor or even change their values, then I'd rather do that just to make the clock respond correctly.

Any ideas?