I'm trying to increase my knowledge of electric circuits and their major components. My current understanding is very basic, which will explain why my question may seem laughable to most people on here. Regardless, I'm hoping someone can water down an explanation for me regarding operational amplifiers. After a bit of reading and looking for explanations, the common thread is that:
In an ideal amplifier, current does not flow into or out of the inputs (there is 0 input bias current). However, I keep hearing that you essentially "put in" a voltage. I'm unclear as to how one can input a voltage while supplying no current.
I understand how there can be voltage without current flow (say, if a point charge is present but not moving in space). But in amplifier inputs, the important part seems to be "inputing" a voltage. I just don't understand how you can supply or input a voltage without moving some charge through the input (at least initially).
If my understanding is so far gone that you do not understand my question, please let me know (and perhaps provide a few resources that you feel describe amplifiers or electronics in an easily digestible way).
Best Answer
An op-amp has what is known as an input impedance. In the most simplistic terms this can be thought of as a resistance to ground. When you connect a voltage to the input current flows through that resistance to ground.
The "ideal" op-amp has an infinitely large input impedance, which means that an infinitesimally small current will flow - i.e., no current. That never happens though.
The thing to remember is that current is the movement of electrons around a circuit, but voltage is simply the difference in electrical potential between two points in a circuit. Nothing needs to flow for there to be a difference in potential.
Take a simple AA battery, for example. With it disconnected there is no circuit, yet the + terminal is 1.5V higher than the - terminal. The input of the op-amp's input is simply measuring that voltage. But of course, just like in quantum physics, the act of measuring it changes it, because the input impedance isn't infinite, and so some current flows, which then has an effect on the circuit (and hence the voltage) that you are measuring.