About the gain being stated as \$A_V=3\$, the complete relevant text is
R3 and R4 form an output voltage gain stage whose gain, \$A_V=3\$, is reduced to unity at high frequencies by C1 to maintain stability.
What this is saying is that R3 and R4 form a voltage divider so that
$$v_o = \frac{v_{out}}{3}$$
where \$v_{o}\$ is the voltage at the output of the op-amp IC.
Or, turned around,
$$v_{out} = 3 v_o.$$
This works because the negative feedback around the op-amp will cause it to push or pull current from its output pin to make it work.
The overall gain of the circuit is 33, as you calculated.
, it is stated that the gain of the whole circuit is 33 while the gain of the output is 3 . So you can have 2 gains in an op-amp ?
No, the "stage" formed by R3 and R4, with gain 3 doesn't really involve the op-amp.
But even within the op-amp integrated circuit itself, of course every stage in the design can have a different gain value.
So one is the gain of the input to the Vout? and the other is the gain of the op-amp output to the actual Vout?
33 is the gain from \$v_{in}\$ to \$v_{out}\$
3 is the gain from \$v_o\$ to \$v_{out}\$. I think Tim's comment does a better job explaining it than I could:
If the voltage on the op-amp output is not equal to 1/3 of the output voltage (ignoring C1), then current will flow in it's positive or negative power pin. That forms a negative feedback loop composed of the four external capacitors and the op-amps (internal) output stage.
This is a common characteristic of rail-to-rail input op-amps. There are really two front ends and there is a transition between them at some common-mode voltage. R-R output is irrelevant.
If you care about Vos to that extent, you can choose another type of op-amp. Maybe a chopper type, but they have other subtle (and not so subtle) imperfections.
Best Answer
The permissible total supply voltage is given in the absolute maximum ratings at 36V. As always, you should not go right up to the absolute maximum, and 30V nominal might be a reasonable limit since it is specified at +/-15V.
There is no ground pin on this chip, like most op-amps, so the chip has no real way of knowing how the supply is split up, if at all.
However, the input common mode range is only within 2.5 or 3V of each supply, so it may not work properly in circuits designed for “single-supply” op-amps with input common mode range that extends to the negative supply rail.
The output does not swing all that close to either supply rail, so you need to take that into account as well. Single supply op-amps usually swing very close to the negative rail, particularly with a load from the output to the negative rail only (sourcing current only).