Electronic – BLDC Calculation for Back EMF

back-emfbrushless-dc-motorelectricalmathmotor

I have a brushless DC Motor that i am considering buying from hobbyking.com with 2100Kv (RPM/v) i am trying to follow the equation on Wikipedia's motor constants page i have included the equation here but i am having difficulty understanding whether i am using the calculation correctly. Motor Torque Constant

My calculation is 60/(2 x π x 2100) = 0.00454 Nm/A and this should be the value of Kt described above, also because Kt = Ke my back EMF constant will also be 0.00454?

Can anyone help me understand if this is correct?

Best Answer

This is correct.

\$K_t\$ is approximately equal to \$K_e\$ (approximatly as \$K_e\$ is defined as open-terminal voltage and \$K_t\$ is defined at rated current & the machine may be saturating)

\$K_v\$ is the reciprocal of \$K_e\$

The units of \$K_t\$ are \$\frac{Nm}{A}\$

The units of \$K_e\$ are \$\frac{V}{\omega}\$ (NOTE: from a magnetic point of view this is peak line-line voltage...)

so... 2100\$\frac{rpm}{v}\$ == 219.911 \$\frac{rad/s}{V}\$ = \$K_e\$

Thus taking the reciprical of \$K_e\$

\$K_e = \frac{1}{K_v}\$ = 0.0045473

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