I'm having a little trouble with my boolean algebra and I was hoping you all can help me out. I've been given the task of designing a circuit that takes in a binary 4 digit number (X3X2X1X0) and returns '1' if the number entered was even. I'm fairly certain that my truth table is correct, but if someone could look at my algebra for my 'Y' value, it would be greatly appreciated, as I am somewhat unfamiliar with boolean algebra. Thanks in advance!
Electronic – Divisible-by-2 Circuit Help!
digital-logic
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Best Answer
The answer is the inverse of X0
i.e. \$Y = \bar{X_0}\$
It's clearly this because if \$X_0\$ is 1 then the number is an odd number. Sometimes you've just got to look at the truth table without thinking much about boolean algebra.