How XCHG instruction is executed by 8085 microprocessor ? By default XCHG instruction takes place between DE pair and HL pair. Suppose let us assume contents of DE pair is replaced by the contents of HL pair, then how contents of HL pair are replaced by the contents of DE pair, because it is already replaced by contents of HL pair. How this is possible ?
Electronic – Exchange instruction of 8085 microprocessor
microprocessor
Related Topic
- Memory-mapped I/O and Peripheral-mapped I/O in 8085 microprocessor
- Electrical – Invalid opcodes
- Electronic – How many stall cycles resulted by incorrectly predicted branch in instruction pipelining
- Electrical – Understanding branch delay slot and branch prediction prefetch in instruction pipelining
- Electronic – 8085 MPU; Stepping through an instruction (Timing diagrams)
Best Answer
In Verilog HDL: