# Electronic – get base current in transistor circuit

transistors

I am given a circuit with a transistor and I have to calculate base current. To do that I am using the formula for the linear load:

$$I_c = – \frac{1}{R_c} \cdot U_{CE}+ \frac{U_{CC}}{R_C}$$

And the given values:

current boost factor: \$B = 400\$

\$U_{CC} = 11V\$

\$U_{BE}=0,7V\$

\$R_C=3,3k \omega = 3,3 \cdot 10 ^{3} \Omega\$

\$R_E = 5 k \Omega = 5 \cdot 10^3\$

\$R_1 = 55 \Omega\$

\$R_2 = 7 \Omega\$

So I have tried to use the values to get \$U_{CE}\$.

$$I_c = – \frac{1}{R_C} \cdot U_{CE} + \frac{U_{CC}}{R_C}$$
$$0 = – \frac{1}{3,3 \cdot 10^3} \cdot U_{CE} + \frac{11V}{3,3 \cdot 10^3}$$
$$– \frac{11V}{3,3 \cdot 10^3} = – \frac{1}{3,3 \cdot 10^3} \cdot U_{CE}$$

$$11 V = U_{CE}$$

Question: Does that make any sense? That would mean that \$U_{CE}\$ always equals \$U_{CC}\$? What is the right way to solve that task ?