I can't see how a resistor placed on a whole other input terminal has anything to do with compensating this input bias. i.e. the input stages are just the gates of transistors of differential stage. In this circuit, one of them is completely connected to ground and has no current to flow FROM or TO the op-amp.
This is saying that the non-inverting transistor has a current flowing from its collector to its gate. (At least the way I understand it.)
The most common compensation involves adding a resistor [R3] to the standard inverting amplifier to cancel out bias currents [output offset].
The compensation resistor [R3] causes a current, on the positive terminal, equal and opposite to current flowing into the negative terminal.
So any DC output offset caused by the inverting input is cancelled by the non-inverting input.
The value of R3 should be equal to the parallel combination of R1 [Ri] and R2 [Rf].