loadresistors
Use max power transfer theorem to calculate the value of RL for the following circuit.
I've done the Thevenin's equivalent circuit but from there I don't know how to find the \$R_{Load}\$. I need it to do a table of current and power against \$R_{Load}\$.
Any suggestions or help would be appreciated.
If you're looking for Rth, you do exactly as you said (remove RL such that there is an open-circuit between A and B, then shut V2 off and measure equivalent resistance from A to B).
First, remove the resistor and short V2. If you label nodes at this point, it will help you to redraw the circuit in a more typical fashion:
Convince yourself that that is true, and from there you should be golden :)
The trick here is to look at the spacing. It's subtle, but when you know what to look for it's obvious.
The right-hand band of the top resistor has a slightly wider space infront of it. That's the % band.
So you have Brown Black Black Silver, at Brown %, which is
100×10-2Ω at 1%. (1Ω±1%)
The bottom one, the left hand band has a slightly wider space. That's the % band. As I say, subtle differences. The top one is more obvious than the bottom one.
So you have Brown Black Black Brown at Brown %, which is
100×101Ω at 1%. (1kΩ±1%)
Best Answer
The "maximum power transfer theorem" tells you that for maximum power transfer, the load resistance must be the same as the source resistance.
You've used Thevenin's theorem to find the source resistancee. Given that and the statement above about the maximum power transfer theorem, you should be able to figure out \$R_{Load}\$ pretty easily.
From that you can find the current through the circuit and the current through \$R_{Load}\$.
With the current through \$R_{Load}\$, you can find the dissipated power using the formula for Joule heating. That's \$P_{Load} = I_{Load}^2R_{Load}\$