Electronic – Microwave oscillator conditions

microwaveoscillator

The conditions for a negative resistance microwave oscillator are (2-port):

  1. \$K < 1\$ (unstable device)
  2. \$Γ_{in} \cdot Γ_g = 1\$ (condition for oscillating input port)(generator side)
  3. \$Γ_{out} \cdot Γ_l = 1\$ (condition for oscillating output port)(load or termination side)

Where \$Γ_{in}=s_{11}\$ and \$Γ_{out}=s_{22}\$ (\$s_{11}\$ and \$s_{22}\$ are S-parameters)

Can anybody please explain the logic behind the 2nd and the 3rd condition?

Best Answer

The passive terminations \$Γ_g\$ and \$Γ_l\$ must be added so that the input and output resonate at the same frequency of oscillation. For this purpose, the 2 and 3 conditions are used. In other words, if the oscillator is oscillating at one port then it has to oscillate at the other port too.

there's a proof too for two port oscillator design. Suppose oscillation condition is met at port 1 then from second condition,

\$ \dfrac{1}{Γ_{in}}=Γ_g \$

Now we know, \$Γ_{in} = s_{11} + \dfrac{s_{12} \cdot s_{21} \cdot Γ_l} {1-(s_{22} \cdot Γ_l)} \$

substituting Γin formula in the equation, we can easily get, \$ \dfrac{1}{Γ_{out}}=Γ_l\$.

And hence if one port is oscillating then the other port has to oscillate simultaneously. And thats what condition 2 and 3 convey.