# Electronic – MOSFET Over Heating. So hot it’s melting the solder

heatmosfet

Alright, continuing with the debugging of my new board tonight I found another issue worse than the one before: My switching MOSFET is getting so hot that I'm getting molten solder.

I replaced the MOSFET with a short circuit just to see if the components sorounding the MOS were the cause of the problem (mostly a big Inductor I have right next to it) but the copper reaches a temperature of 110°F, not enough to melt solder.

This is my schematic:

As you can see, my VGS is around -11V and I'm running 3A through it using an Electronic Load. Based on the datasheet of my NTD20P06L-D this thing can do up to 15.5A.

Any ideas of what might be going on?

The only thing I could think of was that the heat on the copper could be increasing RDS(on) but at that particular low current it shouldn't be so serious.

I am using the TO-252-3, DPak (2 Leads + Tab) package.

It sounds like you need a heatsink.

Another thing to check is your gate voltage when you have the FET switched on. If your Gate-Drain voltage is too high, the MOSFET may not be properly biased on, a situation which would generate a lot of heat.

Also, how often is this switching? Is it a steady-state thing, or is this part of a switching supply? If it's a switching supply, you will also need to look at the rate at which the system switches.

Anyways, assuming you have everything biased properly (probably a safe assumption, but measure it anyways):

RDS(on) = 130mΩ @ G-D voltage of 5V

So, with 130 mΩ in series with 3A:

\$\$V = 0.130 * 3\$\$ \$\$V = 0.39\$\$ \$\$Power = V * A\$\$ \$\$Power = 0.39 * 3\$\$ \$\$Power = 1.17W\$\$

So you're going to be dissipating 1.17W of power in the MOSFET, in the best-case situation.
That will get very toasty without a heatsink. If you're just running this as a bare TO-220 device, it getting extremely hot isn't too suprising.

So, assuming we have a TO-220 in free-air:

TO-220 junction-to-air thermal to ambient equals 62.5 degree per watt.

(From here)

Therefore:

\$\$Δ°C = 62.5 * 1.17\$\$

\$\$Δ°C = 73.125\$\$ \$\$Device Temperature °C = 73.125 + Ambient\$\$ \$\$Device Temperature °C = 98.125\$\$

So assuming ideal thermal dissipation on a bare TO-220, it's still going to easily reach ~100°C.
Any environmental factors that further reduce the device's cooling will make it worse.