The question says:
Design an op amp circuit with inputs \$v_1\$ and \$v_2\$ such that
\$v_o = 3v_2-5v_1\$
One way to realize this circuit is to utilize difference amplifier which satisfies this equation
$$
v_o = \frac{R_2(1+R_1/R_2)}{R_1(1+R_3/R_4)} v_2 – \frac{R_2}{R_1}v_1
$$
for this circuit
Unequivocally, \$\dfrac{R_2}{R_1}=5,\ \ \dfrac{R_2(1+R_1/R_2)}{R_1(1+R_3/R_4)} =3 \implies R_2=5R_1, R_3=R_4\$. If \$ v_1=6, v_2=2 \implies v_o=3v_2-5v_1=3(2)-5(6)=-24\$. Using PSpice to realize this circuit, I'm getting different result
Best Answer
With the input voltages present, the output would need to be -24 volts but, it's likely that the power rails applied in OrCAD are limiting the output to +/- 15 volts hence, you get negative clipping.
Try inputting 0.6 volts and 0.2 volts to get -2.4 volts on the output.