Let's say I have an INA134 (http://www.ti.com/product/ina134) from Texas Instruments in my design. I want to take the output of that IC and feed it into a resistor network which can have a flexible input resistance (from 100 ohm to 100k ohm).
What is the reason that the output impedance of the IC is not specified in the datasheet? It's based on a simple opamp circuit after all.
Does it make sense to follow the INA134 by a OPA134 to allow for more drive capability?
Best Answer
The output drive capability is defined in a few places in the datasheet, but not guaranteed except at 2K load. The below graph is based on +/-18V supplies.
As you can see you can get 20mA easily out of it, with 15V swing. With a 100R load, the output capability would be a couple of volts or so safely.
I don't see why you'd want to follow this part with another such as the OPA134 that has similar or less current capability.
Keep in mind that the closed-loop output impedance on both amplifiers will appear very low, up until the point where you hit the current limit (or when thermal protection kicks in).