Electronic – Parallel windings on a solenoid coil

coilinductorsolenoid

Suppose I have a fixed voltage supply of 10 V and I need to get 20 amp-turns from my solenoid coil but my solenoid coil with 10 turns is 10 ohms, so I am getting 10V/10 ohms = 1A, 1A * 10 turns = 10 amp turns.

Can I take my coil and instead take the wire and cut it in half and wind both halves at the same time. So now I have two 5 turn coils in parallel, each with 5 ohms resistance. So I do the calculation and get
10V/5 ohms = 2A for each coil, 2A * 5 turns = 10 amp-turns for each coil,
So now I have 20 amp-turns total on my coil.

Therefore making my solenoid 4 times stronger?

Is this right or am I missing some fundamental law of electromagnetism?

Thank you

Best Answer

"stronger" is not very scientific, it could mean many things. If you measure strength in Amp*Turns, your solenoid is twice as strong after the modification. If (as I understood from comments) you're considering the electromagnetic pull force which is proportional to (I * N)2, then your new solenoid is 4 times as strong.

Also, if your solenoid is small enough, its core may go into saturation before you reach maximum current. Increasing the current further in that case will have practically no effect on the pull force.