The device is a Banana Pi M3, I accidentally short it out when I was playing around with my multimeter on the GPIO pins…. A noticeable spark came from that component in the above picture circled in red. Hopefully, only that component got burnt and nothing else, so I can replace it.
At first I thought it was a resistor or a capacitor, but I was wrong, I think. I'm guessing it's an SMD ferrite bead judging from the manufacturer's schematics. Schematics. I think it's the third page labelled PMIC where it shows an USB connector along with a DC in symbol.
Problem is, the values aren't labelled in the schematics, so I won't know what ferrite bead to order, the only thing I can tell from looking at it is that it's a 0603.
I have this multimeter: "INNOVA 3320 Auto-Ranging Digital Multimeter," from Amazon (Sorry, I can't post more than 2 links), if that helps. I don't mind buying new equipment, this is a learning experience type thing for me. Thanks.
Edit: Just a little detail as to how this happened. When I was playing with my multimeter, I put the negative probe to GPIO pin 2 and the positive probe to GPIO pin 6, I accidentally moved the positive probe around making it touch either pin 5 or pin 8 or both while still touching pin 6. The GPIO layout is the same as Raspberry Pi Model B+, or at least that's what the makers said.
Best Answer
My supposition:
It is a ferrite bead, and it is being used, along with the capacitor next to it, as a small filter on the power supply.
It is a 'non critical' component and only really has any affect when you're using a noisy power supply.
You should be able to replace it with pretty much any 0603 ferrite bead. Lower DC resistance is better as it reduces the voltage drop across it.
You could even replace it with a blob of solder to get it working again.