Electronic – the practical use of Laplace Transform

induction motorlaplace transformpower electronicsrotorthree phase

I am trying to understand the electrical model of 3-phase Induction Model. The rotor of the motor is modeled as a variable resistor in s-domain.

I fail to understand how that works practically. Can anyone explain me the practical relevance of LT and its use in the IM modelling?

Your help is highly appreciated.

edit: This is the link of the IM model: When load increases in rotor of induction motor how does stator draws more current?

Best Answer

The "s" that you are referring to is not the "s" of the Laplace Domain. It is called "slip" and the definition is

\$s = \frac{n_R}{n_S} = \frac{n_S-n}{n_S} = 1 - \frac{n}{n_S}\$

where

\$n\$ is the rotational speed of the rotor

\$n_S = \frac{f_S}{p}\$ is synchronous rotational speed

\$n_R = n_S - n\$ is the relative rotational speed

\$f_S\$ is the electrical frequency - typically 50 or 60 Hz

and finally

\$p\$ are the # of poles of the stator

So, slip is a measure of how away the rotor speed is from the synchronous speed.

Any textbook provides the proof of how mechanical power can be represented by the power that is consumed by a resistor, the value of which is \$R_R\frac{1-s}{s}\$


Laplace Domain is basically a tool for solving the ODEs, by make them linear equations - it also gives information for the spectral content of the system, but that is a different story.