Electronic – thevenin equivalence of wheatstone bridge load
circuit analysis
I'm trying to figure out the Thevenin equivalent as seen from the load of a wheatstone bridge… however, I think the model example in the book is wrong:
Here's what the book has to say:
Here's my work:
Which is the right answer?
Best Answer
Looks like you are. They're making an algebraic error, assuming that adding conductances is the same as adding the associated resistances (initial equation is wrong). They further compound it by combining parallel resistors wrongly...the parallel resistances should each have their own reciprocol, not share the same denominator.
You need to consider the sources separately, one at a time, and then combine (add together) their effects to determine the final result.
For example, when considering the 16V source (reference designators would be helpful here), replace the current source with an open circuit. What is the Thevenin equivalent now?
Next add the current source back in. What kind of offset does this introduce into the Thevenin equivalent resistance?
I think capacitor and resistor are in series but then they combined are in parallel with a piece of wire which has least resistance(impedance in AC) so i think total impedance would be 2k
Best Answer
Looks like you are. They're making an algebraic error, assuming that adding conductances is the same as adding the associated resistances (initial equation is wrong). They further compound it by combining parallel resistors wrongly...the parallel resistances should each have their own reciprocol, not share the same denominator.