Electronic – Understanding this simple FM receiver

fmradioreceiver

I know the theory of FM, but I just can't understand how this simple circuit works. So let's say a radio station is transmitted on 100 MHz, as I understand in this case the oscillator should also produce a 100 MHz sign. What I don't get is, how the FM bandwidth (which is around 100 MHz in a range) is picked up from the antenna and demodulated?

Could you please explain how this circuit works?

Thanks!

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Best Answer

The inductor L, the capacitor C and multiple (intrinsic) capacitances of the transistors form an parallel LC-tank circuit with resonance frequency of about 100MHz. The trim-capacitor C allows tuning this LC-tank resonance frequency.

Such a parallel LC-tank has its highest impedance at resonance frequency, thus it also has its highest voltage at resonance frequency. Every frequency deviation from resonance frequency leads to an amplitude change of the voltage at the left terminal of C1. This voltage is then coupled through C1 to the earphones.

For the FM-demodulation to work, the LC-tank has to be tuned a bit off resonance, so that the radio works on the slope of the resonance curve and thus the change of frequency results in a (mostly) linear change of voltage (this technique is called slope demodulation).

So in the end, this LC-tank acts like a (delta-) frequency to (delta-) voltage converter which is the basic function of an FM-receiver.