Electronic – Why does this simple FET circuit behave this way

fetled

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In the circuit above, when S1 is pressed and released, the LED turns ON and stays ON. Why is this so? I can't directly measure the Gate Voltage with a DMM since connecting the DMM results in the LED not staying ON.

If the LED is ON (S1 pressed then released), when S2 is pressed and released, the LED turns OFF, as expected.

I skimmed my intro ECE book chapter on FETs and it didn't seem to mention anything about this phenomenon…

Best Answer

When you press S1, you're storing a charge on the gate which has a small capacitance Cgs. This charge maintains the electric field which keeps the channel between the drain and source. Once you press S2, the charge on the gate is deplected and the channel is turned off

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