led
My goal is to take a typical white clock and make it light up green at 3pm, yellow and 6pm and red at 9pm
I'm guessing I'm going to need 6 red led lights, 6 yellow led lights and 6 green led lights
What I'm not sure about is how something on a timer switch would be wired up, would I use transistors, diodes or something else
The clock is run off of 2 AA batteries
With the LED panels, you shouldn't need any sort of current limiting resistor or special current driver source - just connect to 12V and go. I can't say they are the highest quality, but they should work fine for what you are trying to do, although, I think the using RGB LEDs would work better as the different colors would blend better to form white than these separated panels will.
I think this could be solved very easily using many different methods. The best method for you will depend upon what you know how to do. A simple microcontroller with a couple of external buttons and transistor switches would work flawlessly, but if you don't know how to program, that is not a good route. A few logic gates driving transistors with button inputs would also work fine, but I imagine you would have already done that if you knew how.
If you would be interested in seeing a simple logic circuit, let me know and one can easily be provided.
But what about using a couple of different simple switches. Take a look at this circuit:
Switch 1 is 6 pole rotary switch. It uses rotating knob to connect the main input to one of the 6 outputs. There are many types of rotary switches with many poles (number of contacts). You will need at least a 4 pole switch, but a 6 pole switch may be better. I'll explain why in a minute.
Switch 2 is a triple-pole, double-throw switch. It has three different poles, and has two ways to "throw" them. If the switch is throw in one direction, all three LED box positive leads are connected to 12V, so they all three turn on. If it is thrown in the other direction, each LED positive lead is connected to one of the poles on the rotary switch.
If using a 4 pole rotary switch, pole 4 should be left open - this would be all LEDs off. Pole 1 would go to LED 1, pole 2 goes to LED 2, and pole 3 goes to LED 3. As you turn the knob, a different LED will be powered. There are two reasons why a 6 pole switch may be better. First, there could be an off state between each of three LED off states (1 ON, all OFF, 2 On, all OFF, 3 On, all OFF). Secondly, some rotary switches are not completely off in between states, meaning that as you turn the knob, the two adjacent LEDs will both be on for a moment, and I don't think you are wanting that to happen.
The great thing about using the 6 pole rotary switch in combination with the 3PDT switch like this is that no two LEDs can be on at the same time - it's either none, one, or all of them. The down side to using the rotary switch is that you can just select an LED bank to turn on, you might have to cycle through the colors depending on the current state of the switch.
One way to avoid this is to use a third "main power" switch to disconnect power/ground to the whole thing while you select a specific color with the rotary dial. Since you are working with color sensitive paper, this might be the best way to go.
A different way to do it is to replace the rotary switch with three common single-pole, single-throw switches like this:
With this setup, you can easily choose which LED bank to turn on. The bad thing is that you could accidentally turn on more than one at a time if you aren't careful...
Of course, no matter what you do, the switches need to be at least rated for 12V DC and as much current as the LEDs are expected to draw.
There are other mechanical switches that will select one while automatically deselecting other inputs - like how a lot of old RCA selectors used a spring loaded lever to select between your VCR, Nintendo, DVD player, etc to input into the TV RCA jacks. But again, these switch selectors typically allow more than one input to be select as they change states.
This is the simplest circuit I can think of (2 parts):-
simulate this circuit – Schematic created using CircuitLab
Input = 5V Red Input = 0 Green
The circuit works because the \$V_F\$ of a Red LED is generally much less than the \$V_F\$ of a Green or Blue LED.
Here is a typical RGB LED datasheet:
And here are the typical plots of \$V_F\$ vs. current:
When the transistor is "off", the Green LED will have a forward voltage of about 3.0V at 10mA. When the transistor is "on", the Red LED will have a forward voltage of less than 1.9V. Referring back to the Blue/Green graph, little current will flow through the Green LED at that forward voltage.
This particular arrangement shows a common-cathode arrangement, however it could be flipped and a similar P-channel MOSFET used. In that case, 0V would select the Red LED, and +V in would select the Green LED.
Best Answer
Seeing LEDs are diodes, we'll go with a yes to diodes.
Transistors? Very likely if you want to use the clock's LED driver.
You would configure the transistors as logic gates.
The "something else" could be resistors.
Your clock would need to be a digital clock with 7 segment digits.
You would need to know the pinout for the 7 segment LED driver.
You would need to know the driver's current and voltage for each segment.
You would drive the logic gates with with two of the clock's segments.
Build a logic table for the segments when the hour digit is a three, six, or nine. You need a logic combination that will have a unique output for each of these three digits. The outputs of the logic gates would drive another transistor that turns the LEDs off and on. OH! Look, more diodes!
It's not going to be easy to use the drivers in the clock.
Your best bet would be to use a microcontroller with a realtime clock to drive the red, yellow, and green LEDs. It will work with any type of clock, analog or digital.