Equation For Capacitor Leakage Current

capacitordielectricleakage-current

I'm finding a bit of a problem when trying to solve this question:


Show that the leakage current for the capacitor is given by
\$ I = \dfrac{Q}{KP} \$


where \$Q\$ is the charge on the plates, \$K\$ is the dielectric constant and \$P\$ is
the resistivity of the dielectric.

I know the concept behind the leakage current and why it happens, but I don't know how I can prove the equation.

Best Answer

Current is defined as voltage divided by resistance.

Therefore, you need to find a way to relate charge to voltage, and resistivity to resistance.

Voltage on a capacitor is charge divided by capacitance. Capacitance is related to plate area, spacing and dielectric constant.

Resistance is resistivity multiplied by thickness and divided by area.

Are these hints enough to get you started?