Why is voltage 0 after the last component in a circuit given electron current flows from negative to positive

voltagevoltage measurement

Perhaps a different way to ask my question is why does voltage drop occur on the negative side of a component and not the positive given what is known about electron current? E.g. in the diagram below voltage would read 9v at node2 and 0v at node1. This would make sense if conventional current were true, but electron current makes me feel like the drop should occur at node 2, not node 1.

schematic

simulate this circuit – Schematic created using CircuitLab

Best Answer

Because all instruments still adhere to conventional theory of positive to negative flow instead of the now proven negative to positive flow. In practice, the only thing that matters is that everyone agrees on the same standard, even if the direction is technically "wrong".