Go – “used as value” in function call

What's the proper way of calling functions when evaluating their values in conditional statements?

package main
import "fmt"
func main(){
        if sumThis(1,2) > sumThis(3,4){
                fmt.Println("test")
        } else {
                fmt.Println("derp")
        }
}
func sumThis(a, b int){
        return a+b
}

this returns error:

./test4.go:4: sumThis(1, 2) used as value
./test4.go:4: sumThis(3, 4) used as value
./test4.go:11: too many arguments to return

How would you write this in Go?

Best Answer

You've forgotten to declare a return value. It should be:

func sumThis(a, b int) int {
// ...

Related Solutions

Go – How to convert an int value to string in Go

Use the strconv package's Itoa function.

For example:

package main

import (
    "strconv"
    "fmt"
)

func main() {
    t := strconv.Itoa(123)
    fmt.Println(t)
}

You can concat strings simply by +'ing them, or by using the Join function of the strings package.

C# – linq to entites left outer join

Anybody who tells you to use .DefaultIfEmpty() as part of an outer join in LINQ to Entities hasn't actually tried it themselves! Tt simply does not work - at least as at .NET 3.5 SP1.

This blogger tells you how you should actually do it. Essentially, .NET does outer joins in LINQ to Entities by default, so you should leave out the .DefaultIfEmpty(). For multiple outer joins you have to nest the query groups to keep their context clear.

Best Answer

Related Solutions

Go – How to convert an int value to string in Go

C# – linq to entites left outer join

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