Java – how to parse a big integer from a string?

java

I have a method like this:

Integer.parseInt(myInt)

not this integer becomes to long and I'm getting the following exception:

java.lang.NumberFormatException: For input string: "4000123012"

what can I do to avoid this error and still keep alle the functions runnning?

I tried to use BigInteger but there is no parse method, or I did not found it.

Best Answer

Use it like this.

 BigInteger number = new BigInteger(myInt);

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Java – Create ArrayList from array

new ArrayList<>(Arrays.asList(array));

Java – How to call one constructor from another in Java

Yes, it is possible:

public class Foo {
    private int x;

    public Foo() {
        this(1);
    }

    public Foo(int x) {
        this.x = x;
    }
}

To chain to a particular superclass constructor instead of one in the same class, use super instead of this. Note that you can only chain to one constructor, and it has to be the first statement in your constructor body.

See also this related question, which is about C# but where the same principles apply.

Best Answer

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