Mysql – Defining Composite Key with Auto Increment in MySQL

auto-incrementcomposite-keyinnodbMySQL

Scenario:

I have a table which references two foreign keys, and for each unique combination of these foreign keys, has its own auto_increment column. I need to implement a Composite Key that will help identify the row as unique using combination of these three (one foreign keys and one auto_increment column, and one other column with non-unique values)

Table:

CREATE  TABLE `issue_log` (
`sr_no` INT NOT NULL AUTO_INCREMENT ,
  `app_id` INT NOT NULL ,
  `test_id` INT NOT NULL ,
  `issue_name` VARCHAR(255) NOT NULL ,
primary key (app_id, test_id,sr_no)
);

Of course, there has to be something wrong with my query, because of which the error thrown is:

ERROR 1075: Incorrect table definition; there can be only one auto
column and it must be defined as a key

What I am trying to achieve:

I have an Application Table (with app_id as its primary key), each Application has a set of Issues to be resolved, and each Application has multiple number of tests (so the test_id col)
The sr_no col should increment for unique app_id and test_id.

i.e. The data in table should look like:

enter image description here

The database engine is InnoDB.
I want to achieve this with as much simplicity as possible (i.e. avoid triggers/procedures if possible – which was suggested for similar cases on other Questions).

Best Answer

You can't have MySQL do this for you automatically for InnoDB tables - you would need to use a trigger or procedure, or user another DB engine such as MyISAM. Auto incrementing can only be done for a single primary key.

Something like the following should work

DELIMITER $$

CREATE TRIGGER xxx BEFORE INSERT ON issue_log
FOR EACH ROW BEGIN
    SET NEW.sr_no = (
       SELECT IFNULL(MAX(sr_no), 0) + 1
       FROM issue_log
       WHERE app_id  = NEW.app_id
         AND test_id = NEW.test_id
    );
END $$

DELIMITER ;
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