I'm using a 12V adapter and a 2S 7.4V Li-ion battery to power my electronics, and I would also like to power my MCU with it. To switch between the adapter and battery I'm using a BQ24133 from TI.
I will use an STM32L4 MCU and some other components that use 3.3V on a custom PCB. Everything together on 3V3 uses up to 150 mA when in full operation mode.
I'm searching for the best/cheapest solution.
1. What is the difference of using buck converter vs linear linear regulator to power an MCU?
2. Would a linear regulator (small packages) be a bad idea because it would heat up a lot because there is a big difference in voltage (12-3.3=8.7, 8.7*0.15=1.3W) ?
3. Would the frequency of switching, or output voltage ripple (noise) be a big influence on the normal operation of an MCU?
4. Conclusion, what is the best way to power it with the input voltages between 6V and 12V?
Thank you for you patience and your answers.
Thank you for all your answers. You all were very helpful. Up until now I used linear for my projects, but I think now I might go buck. If you wanna follow up the reason I asked this, and see what I am making, follow this link
Best Answer
1) Buck converter is:
But it is indeed much more power efficient, especially if there is a big difference in the input voltage vs output voltage, which is your case here. The buck will output almost the same power than it takes at the input (efficiencies are typically ~80-90%), whereas the linear regulator will take as much current as input as it needs to supply (which means that efficiency is Vout/Vin, something like ~27-44% in your case, which is very bad).
2) Yes, this is actually the only reason why linear regulator can be a bad choice: the efficency (and your computation of dissipated heat is fine). Now, having that much power dissipated leads to two big problems:
You will probably need a heatsink (check the datasheet of the linear regulator: at anything more than 1W, you need to check carefully even in TO-220 package. When using smaller packages, it is often not possible at all). So this negates the "more room on PCB" inconvenient of buck regulators.
If you run on batteries, it means much less runtime. Sometimes, you can't afford it (do the computation).
3) Most likely not, if you use standard integrated solutions to do the stepping down. Those are made to provide power to IC chips, and the datasheet/application notes of the step-down controller/regulator you'll choose should give you some information about the amount of noise you'll get. But for digital operation, supply noise isn't typically that much of a problem.
4) Given the huge difference in input/output voltages, the current you need, and the fact you'll partly run on batteries, it seems a logical choice to go for a buck. But you need to double-check all that yourself. Maybe in your case it is acceptable to have a huge TO-220 dissipating 1.3W in your enclosure, and the runtime you need isn't that high.
If you go for a buck, here is what I can suggest: