Electronic – Intuitive explanation for filters

filterpassive-networks

Can anyone provide an intuitive explanation for the filtering action of RC or LC circuits? I know the mathematical treatment involving reactances but I was wondering if that could be explained physically?

Best Answer

The RC low-pass filter (LPF) is the most simple to understand intuitively.

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The capacitor reacts slow to the current it gets, voltage will rise slowly. If \$V_{IN}\$ is a fixed voltage the voltage across the capacitor will rise exponentially until it reaches \$V_{IN}\$. DC is not filtered at all.

If you apply an AC signal current goes back and forth through the resistor, charging and discharging the capacitor. If this goes slowly, at low frequency, the capacitor's voltage can more or less follow the charging and discharging, and its voltage will be near the input voltage. But the higher the frequency the faster current direction changes, and the change will take place before the capacitor is fully charged. So the input voltage is no longer reached. For very high frequencies the changes in current direction are so fast that the voltage amplitude across the capacitor is only a fraction of the input.

We have a low pass filter: low frequencies are passed with little attenuation while higher frequencies are attenuated more.

LC filters are far less intuitive.

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In this parallel circuit part of the current will circulate between inductor and capacitor, and the net current will decrease the closer you get to the resonance frequency. At the resonance frequency the net current is even completely zero, as if L and C aren't there.

In the same way will a series LC circuit form a zero impedance at the resonance frequency, as if there's only the resistor.

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