Three edge-triggered JK flip-flops in a synchronous circuit have the following input conditions.
JA = QB KA = 1
JB = 'QA KB = 1
JC = QB KC = 1
Assume that the initial state is QA = 0 QB = 0 QC = 0
Find the count sequence
I'm having very difficulties how to solve this problem.
And also i found the answer. but no idea how they solved it? can anyone help me
Answer : http://bit.ly/1mhIosR
Best Answer
The characteristic table for JK Flip flop is
As for initial combination mentioned QA = 0 QB = 0 QC = 0
Hence we got 2. Now taking this combination of QA = 0 QB = 1 QC = 0; we can find the next output. In this way the process is repeated until an already produced output is obtained again so that a sequence is formed